Final BOB: Good Luck To All

Hey guys this is the last time I will probably get the chance to blog in this site so I'm gonna take my time saying good luck to everyone who is taking the exam.
Since the exam is tomorrow and today is our last day i wanted to make sure i post a day before the exam just like how we would usually blog on test. The only exception is that this is gonna be the biggest test were gonna have.
In the classes I've spent here I've learned quite a lot of things. Besides math of course we were taught some pretty cool stuff too. For all of you guys who are reading i encourage you to take at least 5-10min from your busy schedule to post up our last blog reflecting this semester.

Why?

Why not? For some of us it will be our last time to blog so why not give it a go, for the others well you can probably just say good luck to everyone.

If there is something i do want to reflect on is how inspiring our teacher is. I for one am sure gonna miss him when we depart. We will someday meet again and everything you taught us we will remember in our own ways. The only thing i regret is that our time with you was short, but the memories last for a life time so i guess that compensates it.

Good luck to you our teacher. With patients and skills you taught us what we need to know. Now it is our turn to take the test and try our very best to succeed with the knowledge you provided us.

Once again good luck to everyone who will be taking the exam and don't over strain yourself in studying at the last minute. Take a break, look over the notes, have a little fun, and have plentiful of a good nights rest. When the exams comes your efforts will be tested.

Good luck again to everyone

Hope you do alright

Bobing for conics

ha ha made a mistake there =P
k for this up coming test i made sure to keep an eye out on the hyperbola because i thought that it might be the hardest in the conics unit.
-hyperbola is identified by having both x^2 and y^2 and is the difference between the two
-opens vertically if y is positive and horizontally if x is positive
-finding the foci is found by add the square of the minor transverse axis and minor conjugate axis. Like a^2 + b^2 = c^2
The rest of the conics; circle, ellipse, and parabola I'm gonna go over some more.
Best of luck guys for tomorrow!
Oh one last thing i just remembered about conics, remember the pattern i think or the geometry of the object in order to give yourself a picture.
I believe that's what I'm trying to say...
ha ha well good luck again!

BOB COMBO!!!

Combinatorics is pretty cool thing so far that i can relate to many things. The possibilities of rearranging the number of objects like horses in a race, to number of ways people can sit in the theater.
First part of Combinatorics was easy to begin with but as we progressed further into it we found more difficult questions. I still have a hard time using the formulas and which to use at certain problems. I got really familiar with the permutations and pick formula but i need to work on the choose formula. If you don't read the question right like what i do sometimes you end up working the question with the wrong formula and end up with a really different answer.
Well i just need to practice harder and try my best for the up coming test.
Good luck to everyone!

Timeline

• May 1: Question 1 created
• May 6: Question 2 created
• May 11: Question 3 and 4 created
• May 18: Final Question created
• May19-25: Final editing of the 5 questions
• May 30: Creating Presentation
• June 5: Final due date of Presentation

April 14/09

Hello everyone. In today's class we started off talking about multiplying big numbers such as the one on the slide. Multiplying 1024*4096 in your head is difficult, so what John Napier created was instead of multiplying 1024*4096 in your head change them into a power with the same base (2^10 * 2^12) and just add the exponents together to find the answer (2^22). Here adding is a lot more easier then just multiplying big numbers.

Later we started putting together tables of value (slide #2) and found that there were patterns to how exponents work. Any base with an exponent of 0 is equal to 1, and powers with negative exponents decrease but never reach 0.

On slides 3 and 4 notice that none of the graphs doesn't go below the horizontal line unless the base is negative. If the exponent is negative it only decrease but does not become 0.
On the next slide (slide #5) something really cool happens. Notice that the base is negative and in close brackets. The slide shows what the power of (-2)^x looks like when graphed, as you move the the right it will show you the values of x but values of y will vanish.

Moving on we went into the subject of sketching the inverse of f(x)=2^(x-2) (as seen on slide# 6). First sketch the f(x)=2^(x-2) on the graph. The x,y values of what you get from the graph are switched around when you sketch the inverse. Any values that are on the blue dotted line stays the same. Slides 7 and 8 is another example.

When you put rewrite the table of values to their inverse (slide #9) their values are switched with the other.

The final discussion in class talks about the anatomy of a power and also logarithms. (slide #10) In a power there is a base and an exponent, together they are called a power. (slide# 11) In logarithms it is like the inverse of a power, there is a base and a power equalling an exponent. As it is mentioned in the slide logarithms is a power.

I apologize that I posted late and that the next scribe volunteered in class.
So thanks and again sorry i posted late

BOB

This Unit went by like rocket and now is coming to its end.
The most memorable thing about it was probably the dance that we learned while learning it. With more and more practice im sure everyone will do great on the test, who knows we might have to use the dance again later on.

Alright well then good luck guys on the test!

Friday March 6 Scribe

Hey guys this is Darryl, and today we had a quiz.
Instead of explaining the process and steps to how we got the answer to all of the questions, ill try to explain what we did on the ones where there were difficulties.

Question 1 was pretty easy so we'll skip on to question 2. (referred to slide #3)
On question 2 the answers were: a) f(x)=g(2x) and b) g(x)=f((1/2)x)
The reason for that is there were no changes within the y-axis only the x-axis and that no shifting occurred. The green line that shows in the graph is what the function would look like if it did shift over to the right.
So then the only thing that changed was a stretch or compress on the x-axis.

Question 3 (slide #4)
A way to help find the answer is to make a dotted line of y=x the same blue dotted line showed on the slide. There you will notice points of f(x) on the dotted line, those points will be the same on f-1(x), from there you can make an inverse line of f(x) with the (x,y) values switched.
On the slide you will notice that f-1(x) does not equal 1/f(x). It was put there as a reminder that f-1(x) is a notation.

Question 4 (slide #5)
Question a is a simple question so i'll skip this one

b)f(x)= -sin(x) is odd because f(-x)= -f(x)
f(x)= -sin(x)
f(-x)= -sin(-x)
-f(-x)= -(sin(-x))
f(x)= -sin(-x)

c) is even because anything in absolute number is positive.

d) is neither because if you follow the process determing whether or not its a odd or even, the final process leads you to neither.

On slide 6 shows steps to reciprocal function graphs and must not be confused with inverse. This is very helpful with the last slide where we have to sketch the following function.

Another thing mentioned in class was Isometric transformations and Lattice Points.
From what i believe an Isometric transformation is bascially a mirror reflection, no stretching or shifting is done but simply turned around at an angle keeping its shape and form.
A definition of a Lattice Point is a point that is a whole number (positive or negative) on the coordinate plane.

Okay well thats all i have for today, sorry if anything i wrote confused you guys I'm pretty bad at explaing. If is confusing or wrong leave a comment on and ill check over it. My first time ever blogging or scribing :D
Oh before i end this ive got a couple of reminders, if you guys havent yet made a delicious account yet try to make one asap.
Also Pi approximation day is on Friday so dont forget to buy Pi
For the next scribe i choose "ianayana" good luck
darryl signing out :D